本文透過研究玻璃材料的選取方法，來找出色差最小的三片稜鏡組合。由於真實光線的公式較為複雜，故本文先做三波段 F-line (0.4861 μm)、d-line (0.5876 μm)、C-line (0.6563 μm) 近軸色差校正，在總偏向角Dd 固定為3度及校正一次色差𝜀F,C和二次色差 𝜀𝑑,C條件下，可求得三片稜鏡的個別偏向角，而後新增 F-line 至 d-line 間的中間 波段 A-line (0.5369 μm)，與 d-line 至 C-line 間的中間波段 B-line (0.6219 μm)，即五段波長之超消色差校正。
經過推導後得出的材料選取方法−視圖法，即比較材料 𝑃d,C−𝑃A,B 與𝑃d,C−𝑉d 之圖，能快速且有效地獲得色差較小之三片玻璃稜鏡組合。而本研究將以視圖法為基礎所挑選出的三片玻璃稜鏡組合，輔以撰寫優化的MATLAB 程式，對視圖法所選取的三片玻璃稜鏡組合優化，以取得真實光線之最小色差的結果。

The goal of this research is to obtain a triplet prism combination with least chromatic aberration by selecting glass materials. For the complexity of the real ray chromatic aberration formula, first we corrected the paraxial chromatic aberration of F-line (0.4861 μm), d-line (0.5876 μm) and C-line (0.6563 μm), we obtained each deviation angle of a triplet prism by fixing the total d-line deviation angle at 3 degree and corrected the primary chromatic aberration 𝜀F,C and the secondary chromatic aberration 𝜀𝑑,C. Then we defined two wavelengths A-line (0.5369μm) and B-line (0.6219μm), where A-line (0.5369μm) is the wavelength between F-line (0.4861 μm) and d-line (0.5876 μm), and B-line (0.6219μm) is the wavelength between d-line (0.5876 μm) and C-line (0.6563 μm). After that we corrected their chromatic aberration to obtain a super-achromat triplet prism corrected at 5 wavelengths.
Deriving the formula of paraxial chromatic aberration of a triplet prism, we are able to obtain a diagram method which can quickly obtain a triplet prism combination with small chromatic aberration. The method is achieved by comparing the area ratio of the 𝑃d,C-PA,B and Pd,C-Vd figures of the materials. After applied diagram method to select a triplet prism combination, we write an optimization code which is based on damped least square method to minimize the chromatic aberration. Then obtain a triplet prism combination with the least real ray chromatic aberration.

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